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Download file - ExifEditor1.1.14.zip. FAST INSTANT DOWNLOAD Download type. ExifEditor 1.1.14. Exif editor you prefer a program for image editing EXIF and IPTC metadata on Mac. The simplest and easiest way. Very brief introduction program. Typical problems that the program decides. Typical problems that the program decides. Change the name of the author and copyright; Changing the location of the photo you shot.

ExifEditor 1.2.2


Exif Editor is your preferred program to edit image EXIF and IPTC metadata on the Mac.
The easiest and the simplest way.
A very brief introduction of the program
Typical problems that the program solves
  • Modifying author's name and copyright
  • Changing location of the photo you shot
  • Correcting time the photo was shot
  • Viewing and editing camera settings
  • Removing camera, author or software information
  • Adding information about scanned analog photos
Basic features
  • Manage and modify metadata directly inside your photos.
  • Supports subset of EXIF and IPTC metadata standards.
  • Edit or remove the data.

What's New:

Version 1.2.0
  • new date/time editor
  • updated exiftool
  • support for HEIC format
  • bug fixes

Screenshots:

  • Title: ExifEditor 1.2.2
  • Developer: Martin Novak
  • Compatibility: macOS 10.15 or later
  • Language: English, Czech, French, German, Simplified Chinese, Spanish
  • Includes: K'ed by TNT
  • Size: 13.69 MB
  • View in Mac App Store

NitroFlare:


The z-score

The Standard Normal Distribution

Definition of the Standard Normal Distribution

The Standard Normaldistribution follows a normal distribution and has mean 0 and standard deviation 1

Notice that the distribution is perfectly symmetric about 0.

If a distribution is normal but not standard, we can convert a value to the Standard normal distribution table by first by finding how many standard deviations away the number is from the mean.

The z-score

The number of standard deviations from the mean is called the z-score and can be found by the formula

x - m
z =
s

Example

Find the z-score corresponding to a raw score of 132 from a normal distribution with mean 100 and standard deviation 15.

Solution

We compute

132 - 100
z = = 2.133
15

Example

A z-score of 1.7 was found from an observation coming from a normal distribution with mean 14 and standard deviation 3. Find the raw score.

Solution

We have

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x - 14
1.7 =
3

To solve this we just multiply both sides by the denominator 3,

(1.7)(3) = x - 14

5.1 = x - 14

x = 19.1

The z-score and Area

Often we want to find the probability that a z-score will be less than a given value, greater than a given value, or in between two values. To accomplish this, we use the table from the textbook and a few properties about the normal distribution.

Example

Find

P(z < 2.37)

Solution

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We use the table. Notice the picture on the table has shaded region corresponding to the area to the left (below) a z-score. This is exactly what we want. Below are a few lines of the table.

z.00.01.02.03.04.05.06.07.08.09
2.2.9861.9864.9868.9871.9875.9878.9881.9884.9887.9890
2.3.9893.9896.9898.9901.9904.9906.9909.9911.9913.9916
2.4.9918.9920.9922.9925.9927.9929.9931.9932.9934.9936

The columns corresponds to the ones and tenths digits of the z-score and the rows correspond to the hundredths digits. For our problem we want the row 2.3 (from 2.37) and the row .07 (from 2.37). The number in the table that matches this is.9911.

Hence

P(z < 2.37) = .9911

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Example

Find

P(z > 1.82)

Solution

In this case, we want the area to the right of 1.82. This is not what is given in the table. We can use the identity

P(z > 1.82) = 1 - P(z < 1.82)

reading the table gives

P(z < 1.82) = .9656

Our answer is

P(z > 1.82) = 1 - .9656 = .0344

Example

Find

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P(-1.18 < z < 2.1)

Solution

Once again, the table does not exactly handle this type of area. However, the area between -1.18 and 2.1 is equal to the area to the left of 2.1 minus the area to the left of -1.18. That is

P(-1.18 < z < 2.1) = P(z < 2.1) - P(z < -1.18)

To find P(z < 2.1) we rewrite it as P(z < 2.10) and use the table to get

P(z < 2.10) = .9821.

The table also tells us that

P(z < -1.18) = .1190

Now subtract to get

P(-1.18 < z < 2.1) = .9821 - .1190 = .8631

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